试题:
(平面向量)已知|
a
|=|
b
|=|
a
-
b
|=1,则|
a
+2
b
|的值为______.

答案:

我来补答
|
a
|=|
b
|=|
a
-
b
|=1
∵|
a
-
b
|2=|
a
|2+|
b
|2-2
a
b
=1+1-2×1×1×cosθ=1
∴cosθ=
1
2

|
a
+2
b
|2=|
a
|2+|2
b
|2+2|
a
||2
b
|cosθ=1+4+2=7
|
a
+2
b
|=
7

故答案为:
7
 
 
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