试题:
如图,在△ABC的边AB、AC上分别取点M、N,使
AM
=
1
3
AB
AN
=
1
4
AC
,BN与CM交于点P,若
BP
PN
PM
CP
,则
λ
μ
的值为(  )
A.
27
16
B.
16
27
C.
1
12
D.12

答案:

我来补答
AP
=
AN
+
NP
=
1
4
AC
+
1
λ+1
NB

=
1
4
AC
+
1
λ+1
(
AB
-
AN
)

=
1
4
AC
+
1
λ+1
(
AB
-
1
4
AC
)

=
λ
4(λ+1)
AC
+
1
λ+1
AB

AP
=
AM
+
MP
=
1
3
AB
+
μ
μ+1
MC

=
1
3
AB
+
μ
μ+1
(
AC
-
AM
)

=
1
3
AB
+
μ
μ+1
(
AC
-
1
3
AB
)

=
μ
μ+1
AC
+
1
3(μ+1)
AB

所以
λ
4(λ+1)
=
μ
μ+1
1
λ+1
=
1
3(μ+1)
,解得
μ=
2
9
λ=
8
3

所以
λ
μ
=12

故选D.
 
 
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