试题:
(选做题)证明:
(1)已知x,y都是正实数,求证:x3+y3≥x2y+xy2
(2)已知a,b,c∈R+,且a+b+c=1,求证:

答案:

我来补答
证明:(1)∵(x3+y3 )﹣(x2y+xy2)=x2 (x﹣y)+y2(y﹣x)=(x﹣y)(x2﹣y2 ) 
         =(x+y)(x﹣y)2
∵x,y都是正实数,∴(x﹣y)2≥0,(x+y)>0,
∴(x+y)(x﹣y)2≥0,
∴x3+y3≥x2y+xy2
(2)∵a,b,c∈R+,且a+b+c=1,
∴1=(a+b+c)2=a2+b2+c2+2ab+2bc+2ac≤3(a2+b2+c2),
∴a2+b2+c2,当且仅当a=b=c 时,等号成立.
 
 
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