试题:
(本小题满分13分)设等差数列满足.
(1)求的通项公式;
(2)求数列的前n项和Sn及使得Sn最大的序号n的值.

答案:

我来补答
解:(1) 由
  解得  
··························································································· 6分
(2) 由 (1) 知,
 
∴当n = 5时,Sn取得最大·········································································· 13分
 
 
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这些题目你会做吗?