试题:
(1)计算(
3
2
)-
1
3
×(-π)0+8
1
4
×
42
+(
32
×
3
)6-
(
2
3
)
2
3

(2)已知log189=a,18b=5,求log365.

答案:

我来补答
(1)(
3
2
)-
1
3
×(-π)0+8
1
4
×
42
+(
32
×
3
)6-
(
2
3
)
2
3

=(
2
3
)
1
3
+2
3
4
×2
1
4
+22×33-(
2
3
)
1
3

=2+4×27
=110.
(2)∵log189=a,
a=log18
18
2
=1-log182

又∵18b=5,
∴b=log185,
log365=
log185
log1836
=
log185
1+log182
=
b
2-a
 
 
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