试题:
用递等式计算.
(1)35+180÷20+10(2)(43+17)÷(36÷6)(3)(220+120)÷(20-16)(4)210÷7×22×5.

答案:

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(1)35+180÷20+10,
=35+9+10,
=44+10,
=54;

(2)(43+17)÷(36÷6),
=60÷6,
=10;

(3)(220+120)÷(20-16),
=340÷4,
=85;

(4)210÷7×22×5,
=30×22×5,
=660×5,
=3300.
 
 
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