试题:
先化简,再求值:
m2-6m+9
m2-4
÷(m-
4m-9
m-2
)•
1
m
,其中m是方程2m2+4m-1=0的解.

答案:

我来补答
原式=
(m-3)2
(m+2)(m-2)
÷
m(m-2)-(4m-9)
m-2
1
m

=
(m-3)2
(m+2)(m-2)
÷
(m-3)2
m-2
1
m

=
(m-3)2
(m+2)(m-2)
m-2
(m-3)2
1
m

=
1
m(m+2)

=
1
m2+2m

∵2m2+4m-1=0,
∴m2+2m=
1
2

∴原式=
1
1
2
=2.
 
 
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